
Ling Counter Mobile Legends
“Cyan Finch”
How to counter Ling: heroes strong against Ling, counter items, emblems, battle spells and role matchups.
Heroes counter Ling
Items counter Ling
Blade Armor
Twilight Armor
Antique Cuirass
Wind of Nature
Winter Crown
Immortality
Thunder Belt
Brute Force Breastplate
Dominance IceLing Matchups
| Matchup | Win rate | Games |
|---|---|---|
Saber | 41% | 187 |
Khufra | 42% | 231 |
Akai | 44% | 897 |
Chou | 45% | 232 |
Hayabusa | 47% | 345 |
Wanwan | 58% | 246 |
Granger | 57% | 167 |
Kagura | 51% | 223 |
Layla | 52% | 135 |
Hayabusa | 51% | 323 |
Emblems counter Ling
Tenacity
FirmnessSpells counter Ling
Role Counter Ling
Counter skill Ling
Passive: Cloud Walker
Skill 1: Finch Poise
Skill 2: Defiant Sword
Ultimate: Tempest of BladesTips counter Ling
- Ling never engages in direct combat but rather assassinates weak targets. Therefore, you should not go alone or return if you are low on blood.
- Ling has a lot of advantages in the jungle because he can move between walls. You should not fight Ling in the forest and need to control your vision to know Ling's direction of movement.
- You should use Aegis or anti burst damage items. You will prevent Ling from killing you quickly with burst damage.
- Use Petrify and CC skills to catch Ling when he attacks you. Skills that can prevent Ling from moving to destroy him quickly.
- Extending the match to the late game, Ling will be nerfed at this stage.
- Ling is quite weak and you can take him down quickly with burst damage. Quickly control the target and deal burst damage before Ling jumps onto the wall.
- Since Ling uses a lot of mana to cast skills, steal Ling's blue buff.
- How to counter Ling in the jungle:
- Control vision and stay away from walls as Ling can pop up out of nowhere to kill you. Prevent Ling from farming the jungle and snowballing quickly in the early game. Pick a hero with good resistance and lots of CC to counter Ling when he rushes you.
- Ling’s Power Analysis:
- Strength:
- Weakness:
- Rate Ling’s strength on a scale of 1 -> 10.









